Problem - Find what interest was earned on an annuity in which you gave $6000 3 years back and now has $6957?
Solution
FV = 6957
PV = 6000
METHOD 1 = NTH ROOT MANNER
(1+R)pow 3 = (6957/6000)
1+R = Cube Root of (6957/6000)
1+R = 1.05
So Rate of return was 5%
METHOD 2 = LOGARITHM MANNER
(1+R)pow 3 = (6957/6000)
Take log on both sides
3 Log (1+R) = Log (6957/6000)
Log (1+R) = 0.0214
In general if we have to find the log of a number what are we finding?
We are finding an exponent to which we will raise the base (in this case 10) to get that number.
e.g Log (100) = Exponent we will raise 10 to get 100 which is 2
In the above case we already have the exponent to which we will raise 10 to get (1+R)
So that means (1+R) = 10 pow (0.0214)
1+R = 1.05
R = 5% in this case also
Reference
http://support.microsoft.com/kb/214116
=LOG(n,b) Log base b of n =LOG(8,2) 3
=(b)^(x) Inverse log of the =2^3 8
number x, base b
=LOG10(n) Log base 10 of n =LOG10(100) 2
=10^(x) Inverse log of the =10^2 100
number x, base 10
=LN(n) Natural log of n =LN(100) 4.6051702
=EXP(x) Inverse natural =EXP(4.6051702) 100
log of the number x
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